MPSC Rajyaseva 2015 GS Paper 1 — Question 55
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पृथ्वीभोवती वर्तुळाकार कक्षेत फिरणाऱ्या उपग्रहा $E_k$ इतकी गतिज ऊर्जा आहे. पृथ्वीच्या क्षेत्रातून बाहेर निसरण्यासाठी किमान केवढी ऊर्जा दिली पाहिजे? A satellite having circular orbit around the earth has a kinetic energy $E_k$. What is the minimum amount of energy to be added so that it escapes from the earth ?
1)E_k/4
2)E_k/2
3)E_k✓ Correct
4)2E_k
Total energy of a satellite in a circular orbit is negative and equals -Ek. To escape to infinity, total energy must become zero, requiring an additional energy equal to its kinetic energy Ek.
Related questions
खालीलपैकी कोणते विधान बरोबर आहे ?
Which of the following statement is correct ?पृथ्वीच्या केंद्रापासून R इतक्या अंतरावर m इतक्या वस्तुमानाचा एका अग्निबाणाला गतिमान होण्यासाठी लागणारी ऊर्जा E = GmM_e (1/R_e - 1/R) इतकी आहे. तर ह्या अग्निबाणाला पृथ्वीच्या गुरुत्वाकर्षण क्षेत्रापासून पूर्णतः निसटण्यासाठी कमीत कमी किती वेग दिला पाहिजे ?
The amount of energy needed to move a rocket having mass m from the surface of the Earth to a distance R from the Earth's center is E = GmM_e (1/R_e - 1/R). What is the minimum velocity, the rocket must have in order to completely escape the Earth's gravitational field ?